Home > 500 Internal > Http 500 Error Java

Http 500 Error Java

Contents

an HTML formatted error page containing and error message and (if you are lucky) a formatted stack trace. Unfortunately, I don't have access to the server I'm calling so I can't see the logs. All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter Contact Us | advertise | mobile view | Powered by JForum | Copyright © 1998-2016 Paul Wheaton FAQs Search RecentTopics FlaggedTopics HotTopics Best Topics Register / Login Post Reply Bookmark Topic Watch Topic New Topic programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Servlets I got http-500 error in servlet and jsp.how to find error? Not the answer you're looking for? http://orgias.org/500-internal/http-critical-http-1-1-500-internal-server-error-linux.html

Dies ist ein 'Catch-All (Sammel)'-Fehler, der vom Webserver erzeugt wird. Either way, you should include all the things you're logging -- stack trace, web request, and app data.  Having all the data right in the email can save you a bunch of time, especially if you're only using your phone.  You can also then just forward it if needed. 5. You can follow him on Twitter, G+, and LinkedIn. Why did my electrician put metal plates wherever the stud is drilled through? http://www.checkupdown.com/status/E500.html

Http Error 500 Internal Server Error

Compute the kangaroo sequence Is the origin of the term "blackleg" racist? Java private static final ThreadLocal> values = new ThreadLocal>() { protected java.util.Map initialValue() { return new HashMap<>(); } }; public static void put(String name, Object value) { values.get().put(name, value); } @Override public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException { try { chain.doFilter(request, response); } catch (Throwable e) { logException(request, response, e); } finally { values.remove(); } } private void logException(ServletRequest request, ServletResponse response, Throwable e) throws IOException, ServletException { HttpServletRequest r = (HttpServletRequest) request; System.err.println("Request.RequestURL=" + r.getRequestURL()); System.err.println("Request.UserPrincipal=" + r.getUserPrincipal()); ... Plant based lifeforms: brain equivalent? Sorry There was an error emailing this page.

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed answers to any questions you might have Meta Discuss the workings and policies of this site About Us Learn more about Stack Overflow the company Business Learn more about hiring developers or posting ads with us Stack Overflow Questions Jobs Documentation Tags Users Badges Ask Question x Dismiss Join the Stack Overflow Community Stack Overflow is a community of 4.7 million programmers, just like you, helping each other. I have done exactly that, and the URL works fine. –user455889 Feb 15 '11 at 7:26 This might be caused by URLConnection sending an invalid Accept header field - try to override it with setReqquestProperty("Accept", "/"); –Julian Reschke Oct 18 '13 at 8:35 add a comment| 2 Answers 2 active oldest votes up vote 1 down vote Unfortunately, I don't have access to the server I'm calling so I can't see the logs. Unfortunately, the server logs would be the best place to look for info on what is causing a 500 Internal Error. 500 Internal Server Error Iis Find the Infinity Words!

Weirder context inside How can I Avoid Being Frightened by the Horror Story I am Writing? Then all I did was add the the no-arg, and it worked. exception org.apache.jasper.JasperException: An exception occurred processing JSP page /jsp/output.jsp at line 19 16: out.println(request.getAttribute("paramlist")); 17: List paramlist=(List)request.getAttribute("paramlist"); 18: 19: Iterator itr =paramlist.iterator(); 20: for (itr=paramlist.iterator(); itr.hasNext(); ) 21: { 22: %> Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:505) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:416) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) person.doGet(person.java:42) person.doPost(person.java:49) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) root cause java.lang.NullPointerException org.apache.jsp.jsp.output_jsp._jspService(output_jsp.java:74) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) person.doGet(person.java:42) person.doPost(person.java:49) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) note The full stack trace of the root cause is available in the Apache Tomcat/6.0.18 logs. -------------------------------------------------------------------------------- Apache Tomcat/6.0.18 karthik ekantha Ranch Hand Posts: 78 posted 4 years ago thank you for your response.need possible this solve this problem Post Reply Bookmark Topic Watch Topic New Topic Similar Threads Module 'null' not found how to solve the error Doubt in JSP Custom tags (Simple Tag) in Dynamic Drop Down Getting error while running BeerStruts example Error JSP - Tomcat All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter Contact Us | advertise | mobile view | Powered by JForum | Copyright © 1998-2016 Paul Wheaton logo-symantec-dark-source Loading Your Community Experience Symantec Connect You will need to enable Javascript in your browser to access this site. © 2016 http://stackoverflow.com/questions/5000697/server-returns-500-error-only-when-called-by-java-client-using-urlconnection-htt karthik ekantha Ranch Hand Posts: 78 posted 4 years ago HTTP Status 500 - -------------------------------------------------------------------------------- type Exception report message description The server encountered an internal error () that prevented it from fulfilling this request.

This time I making it more complicated with including some more classes and services with sharing class objects as parameters between client and server. How To Fix Http Error 500 Conference presenting: stick to paper material? Android Studio for beginners: Code the app Open source Java projects: Docker Swarm Newsletters Stay up to date on the latest tutorials and Java community news posted on JavaWorld Get our Enterprise Java newsletter GO Lightning fast NoSQL with Spring Data Redis Redis isn't your typical NoSQL data store, and that's exactly why it hits the sweet spot for certain... share|improve this answer edited Feb 15 '11 at 10:04 answered Feb 15 '11 at 7:23 Stephen C 388k45413739 Thanks, Stephen - I fear it may take that. –user455889 Feb 15 '11 at 7:30 add a comment| up vote 0 down vote I had the same problem, but fortunately i had access to server logs.

Http Error 500 Wordpress

I think it might be caused by doing a regular request to an SSL host (See the httpS prefix in the url). https://blog.stackhunter.com/2014/01/28/5-ways-to-handle-http-server-500-errors/ One thing not to do on this page is to include an error code or incident number.  Don't turn your customers into your monitoring system.  They shouldn't have to call or email you with an error number.  It's your site.  You know who they are, you know what they were doing, and you know they had a problem. Http Error 500 Internal Server Error exception org.apache.jasper.JasperException: java.lang.NullPointerException org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:522) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:416) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) person.doGet(person.java:42) person.doPost(person.java:49) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) root cause java.lang.NullPointerException org.apache.jsp.jsp.output_jsp._jspService(output_jsp.java:73) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) person.doGet(person.java:42) person.doPost(person.java:49) javax.servlet.http.HttpServlet.service(HttpServlet.java:637) javax.servlet.http.HttpServlet.service(HttpServlet.java:717) note The full stack trace of the root cause is available in the Apache Tomcat/6.0.18 logs. 500 Internal Server Error Youtube share|improve this answer answered May 22 '11 at 15:49 Ted Hopp 163k28240345 add a comment| up vote 1 down vote That error means 'Internal server error'.

Is there any way to safely check expensive electronics on a flight? http://orgias.org/500-internal/http-error-755.html Zusätzlich zu dem an den Client zurückgegebenen 500-Fehler, sollte der Webserver ein internes Fehlerprotokoll erzeugen, das mehr Einzelheiten zu dem was falsch gelaufen ist enthält. Once you start recording web requests with every exception, you'll no longer need to ask your customers silly questions like: "Were you logged in?" "What browser are you using?" "What page were you on?" "What did you type in?" You'll have all of this info and more. Be the first to leave a reply! 500 Internal Server Error Php

Log the Application's State The next big saver is to add your application's state into the mix.  For this I suggest binding a thread-local to each web request.  The advantage of using a thread-local is that you don't need to pass it around to methods, its thread safe, and it can be managed by the servlet filter. asked 5 years ago viewed 5474 times active 5 years ago Blog Stack Overflow Podcast #91 - Can You Stump Nick Craver? Explore the IDG Network descend CIO Computerworld CSO Greenbot IDC IDG IDG Answers IDG Connect IDG Knowledge Hub IDG TechNetwork IDG.TV IDG Ventures Infoworld IT News ITwhitepapers ITworld JavaWorld LinuxWorld Macworld Network World PC World TechConnect TechHive This ad will close in 20 seconds. his comment is here A custom error page won't make your site any more robust or save you time debugging, but it will make you look professional. 2.

Ihr Webbrowser oder unser CheckUpDown-Roboter) zu erfüllen. 500 Internal Server Error Stackoverflow I would like to know whether anyone has attempted something similar wherein the client and the server co-exist within the same web application and the the client is trying to connect to itself. Beheben von 500-Fehlern - CheckUpDown Wir überwachen Ihre Site auf Fehler wie 500.

Browse other questions tagged java http httpurlconnection urlconnection or ask your own question.

You're looking into the problem. e.printStackTrace(); throw new ServletException(e.getMessage(), e); } 1234567891011121314151617 @Overridepublic void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {try {chain.doFilter(request, response);} catch (Throwable e) {logException(request, response, e);}}private void logException(ServletRequest request, ServletResponse response, Throwable e) throws IOException, ServletException {HttpServletRequest r = (HttpServletRequest) request;System.err.println("Request.RequestURL=" + r.getRequestURL());System.err.println("Request.UserPrincipal=" + r.getUserPrincipal());...e.printStackTrace();throw new ServletException(e.getMessage(), e);} 3. sumanta panda Ranch Hand Posts: 224 posted 7 years ago Dear All, Could you please tell me after submitting the page in jsp it will show an error HTTP server 500 error.I am using Sun webser.I keep the jsp,web.xml and servlet file in proper location.But still i am facing same error. Is Currently Unable To Handle This Request. Http Error 500 Try recompiling your servlets using the the target option like javac - target sumanta panda Ranch Hand Posts: 224 posted 7 years ago Thanks a lot Amol Sir....Your advise helped me a lot to achieve my milestone...

else { throw new ClusterException(ioe.getMessage()); } } // HTTP Response message status is OK, then proceed with generating/displaying the response if (urlConn.getResponseCode() == HttpURLConnection.HTTP_OK) { success = true; } } catch (MalformedURLException murle) { throw new ClusterException(murle.getMessage()); } catch (IOException ioe) { throw new ClusterException(ioe.getMessage()); } finally { if (urlConn != null) { urlConn.disconnect(); } return success; } } RELATED TOPICS Java Web Development Java SE Servers Java Language Follow everything from JavaWorld View Comments Recommended Eclipse, NetBeans, or IntelliJ? Is it possible to create a lighter wallet than simplewallet without giving up a view key? Use a Custom Error Page I'll start with an obvious change: replace your server's default error page with a custom one.  Make sure it uses the same branding and theme as your app.  Your error message can be as stoic or funny as the rest of your site, but it should convey that: The error is your fault, not your customer's. weblink Here's the latest code: private String testURLConnection() { String ret = ""; String url = "http://localhost:8080/TestService/test"; String query = "param1=value1¶m2=value2"; try { URLConnection connection = new URL(url + "?" + query).openConnection(); connection.setRequestProperty("Accept-Charset", "UTF-8"); connection.setRequestProperty("Accept-Language", "en-us,en;q=0.5"); BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(connection.getInputStream())); String line; StringBuilder content = new StringBuilder(); while ((line = bufferedReader.readLine()) != null) { content.append(line + "\n"); } bufferedReader.close(); metaRet = content.toString(); log.debug(methodName + " return = " + metaRet); } catch (Exception ex) { log.error("Exception: " + ex); log.error("stack trace: " + getStackTrace(ex)); } return metaRet; } Any help would be greatly appreciated!

Regards Sumanta Panda NewPassword.jsp NewPassword.action=response.encodeURLservlet/customerserviceServlet.NewPasswordServlet ----------------------------------------------------------------- package customerserviceServlet; import dbconnector.OracleDbConnector; import java.util.Date; import java.util.HashMap; import javax.servlet.*; import javax.servlet.http.*; import java.io.*; import java.util.Vector; import log.EnquiryLog; import log.ExceptionLog; import log.GlobalLog; import commonbean.CommonBean; import configBean.Config; import dbconnector.ConnectionPool; import config.SystemMessages ; public class NewPasswordServlet extends HttpServlet { public void init(ServletConfig config) throws ServletException { super.init(config); } public void doGet(HttpServletRequest request, HttpServletResponse response)throws ServletException, IOException { doPost(request,response); } public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { HttpSession session = null; CommonBean commonBean = null; OracleDbConnector dbCon = null; Vector newpasswordVector = null; boolean sessionValidate = false; String series = null; String queryStr = null; String requesttype=null; String userid=null; String dateofbirth=null; String emailid=null; String bankaccno=null; String strTerminal = null; String strUserId = null; String sHostName=null; String strDoGet="Success"; int responseLen = 0; try { requesttype=request.getParameter("rPass"); userid=request.getParameter("txtUserId"); dateofbirth=request.getParameter("DateofBirth"); emailid=request.getParameter("txtMail"); bankaccno=request.getParameter("txtBankAcc"); System.out.println("Request Type"+requesttype); HashMap values = new HashMap(); String procString="PR_ITS_CUSTOMER_AUTH"; values.put("1",userid); values.put("2","dateofbirth"); values.put("3","Types.VARCHAR"); values.put("4","Types.VARCHAR"); GlobalLog.l(userid+"|"+strTerminal+" NewPasswordServlet :: Values="+values); HashMap out = new HashMap(); if(ConnectionPool.interactiveConnectionPool!=null) { dbCon = new OracleDbConnector(ConnectionPool.interactiveConnectionPool); out=dbCon.CallStatementForProcedure(procString,values,Config.itsInterDBName); if(out!=null) { queryStr = (String) out.get("1"); newpasswordVector = (Vector)out.get("2"); } GlobalLog.l(strUserId+"|"+strTerminal+" NewPasswordServlet: B call with queryStr="+queryStr+" Result:"+newpasswordVector); } if(newpasswordVector !=null && newpasswordVector.size() > 1) commonBean.setMessage(""); else{ //commonBean.setMessage("No Corporate Actions Available"); commonBean.setMessage(SystemMessages.getInstance().getMessage("INVALID_SYM")); } commonBean.setresultDetails(newpasswordVector); if(newpasswordVector!=null) responseLen = newpasswordVector.size(); commonBean.setPageTitle("Corporate Actions"); session.setAttribute("commonBean", commonBean); }catch (Exception e) { strDoGet="Failure"; } finally { dbCon = null; newpasswordVector = null; series = null; queryStr = null; } } } ----------------------------------------------------------- web.xml customerserviceServlet.NewPasswordServlet customerserviceServlet.NewPasswordServlet customerserviceServlet.NewPasswordServlet /customerserviceServlet.NewPasswordServlet David O'Meara Rancher Posts: 13459 I like... Is it possible to create a lighter wallet than simplewallet without giving up a view key? Is this common behaviour? –sandeep.ganage Jul 8 '15 at 13:13 1 @sandeep.ganage With the test I used, I first allowed it to fail. I updated my original posting with code. –user455889 Feb 15 '11 at 7:21 It's a server side error, print your request URL in program with params and paste that in browser.

Absent that, you may have to resort to dumping the request headers for the cases that work and the cases that don't work and try to figure out what is different about them. Using a database is just easier.  With one query you'll be able to search across servers, files, users, sessions, threads, etc.  It's even better if your database has full-text search built-in.  And if you put a web interface on it, then your testers and support people can use it too. A Two Faced Coin Changing the presentation of a matrix plot Where are sudo's insults stored? share|improve this answer answered Oct 18 '13 at 7:20 hj3 1 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up using Facebook Sign up using Email and Password Post as a guest Name Email Post as a guest Name Email discard By posting your answer, you agree to the privacy policy and terms of service.

Confused in GET and POST while receiving/sending response from server up vote 5 down vote favorite 1 I am implementing a basic client server architecture using REST services for the first time. First look: Chef’s Habitat puts automation in the app First look: Google Cloud Machine Learning soars 7 habits of highly effective developers 10 hard-core coding tips for faster Python More Insider Sign Out Search for Suggestions for you Insider email Core Java All Core Java Agile Development Java Concurrency Java Language Java Platform Java Security Programming Careers Testing and Debugging Enterprise Java All Enterprise Java Big Data Cloud Computing Data Analytics Development Tools Java APIs Java App Dev Java Web Development Open Source Scripting and JVM Languages Learn Java All Learn Java Design Patterns Mobile Java All Mobile Java Java Android Developers Java iOS Developers News Features How-Tos Blogs Resources/White Papers Newsletters × Close Home Enterprise Java Java Web Development How-To HTTP Status Code 500 Returned - HttpURLConnection to Connect to Web Server Cluster Nodes More like this A recipe for cookie management Server load balancing architectures, Part 2: Application-level load balancing Dodge the traps hiding in the URLConnection class Email a friend To Use commas to separate multiple email addresses From Privacy Policy Thank you Your message has been sent.